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Study Guide: How to Solve: Sine, Cosine, Tangent Problems
Source: https://www.fatskills.com/k-12-assessment-tests/chapter/how-to-solve-sine-cosine-tangent-problems

How to Solve: Sine, Cosine, Tangent Problems

By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.

⏱️ ~5 min read

How to Solve: Sine, Cosine, Tangent Problems

A Complete Guide for Students & Teachers


Introduction

"Master sine, cosine, and tangent, and you’ll solve real-world problems—from measuring skyscrapers to acing your trigonometry exam in under 60 seconds per question."


What You Need To Know First

Before diving into SOH-CAH-TOA, ensure you understand: 1. Right-angled triangles – A triangle with one 90° angle. 2. Opposite, adjacent, and hypotenuse sides – Relative to the angle you’re working with. 3. Basic algebra – Rearranging equations to solve for unknowns.


Key Vocabulary

Term Plain-English Definition Quick Example
Sine (sin) Ratio of the opposite side to the hypotenuse. In a triangle, sin(30°) = 0.5.
Cosine (cos) Ratio of the adjacent side to the hypotenuse. cos(60°) = 0.5.
Tangent (tan) Ratio of the opposite side to the adjacent side. tan(45°) = 1.
Hypotenuse The longest side of a right-angled triangle. Always opposite the 90° angle.
Opposite The side directly across from the angle in question. If angle A is 30°, the opposite side is BC.
Adjacent The side next to the angle (not the hypotenuse). If angle A is 30°, the adjacent side is AB.

Formulas To Know

Formula What Each Variable Means Memorise?
sin(θ) = Opposite / Hypotenuse θ = angle, Opposite = side opposite θ, Hypotenuse = longest side MEMORISE THIS
cos(θ) = Adjacent / Hypotenuse θ = angle, Adjacent = side next to θ (not hypotenuse) MEMORISE THIS
tan(θ) = Opposite / Adjacent θ = angle, Opposite = side opposite θ, Adjacent = side next to θ MEMORISE THIS
Pythagorean Theorem: a² + b² = c² a & b = legs of the triangle, c = hypotenuse Given on exam sheet (but memorise anyway)

Step-by-Step Method

Step 1: Identify the Given Information

  • Look for:
  • An angle (θ) and one side length.
  • Two side lengths (to find an angle).
  • Label the triangle with:
  • Opposite (O) – Across from the angle.
  • Adjacent (A) – Next to the angle (not hypotenuse).
  • Hypotenuse (H) – Longest side (always opposite 90°).

Step 2: Choose the Correct Ratio (SOH-CAH-TOA)

  • If you have O and H → Use SINE (sin).
  • If you have A and H → Use COSINE (cos).
  • If you have O and A → Use TANGENT (tan).

Step 3: Write the Equation

  • Plug the known values into the formula.
  • Example: If θ = 30°, Opposite = 5, find Hypotenuse.
  • sin(30°) = 5 / H → H = 5 / sin(30°)

Step 4: Solve for the Unknown

  • Rearrange the equation.
  • Use a calculator (ensure it’s in degree mode).
  • Example: H = 5 / 0.5 = 10

Step 5: Check Your Answer

  • Does the side length make sense?
  • Hypotenuse must be the longest side.
  • Angles must be between 0° and 90°.

Worked Examples

Example 1 – Basic (Find a Side)

Problem: In a right-angled triangle, angle A = 35°, the hypotenuse is 12 cm. Find the length of the side opposite angle A.

Solution: 1. Identify: Angle = 35°, Hypotenuse (H) = 12 cm, Opposite (O) = ? 2. Choose ratio: We have O and H → Use SINE (sin). 3. Write equation: sin(35°) = O / 12 4. Solve for O: O = 12 × sin(35°) 5. Calculate: O = 12 × 0.5736 ≈ 6.88 cm

What we did and why: - We used sin because we had the opposite side and hypotenuse. - Multiplied the hypotenuse by sin(θ) to find the opposite side.


Example 2 – Medium (Find an Angle)

Problem: In a right-angled triangle, the side opposite angle B is 7 cm, and the adjacent side is 10 cm. Find angle B.

Solution: 1. Identify: Opposite (O) = 7 cm, Adjacent (A) = 10 cm, Angle B = ? 2. Choose ratio: We have O and A → Use TANGENT (tan). 3. Write equation: tan(B) = 7 / 10 4. Solve for B: B = tan⁻¹(7 / 10) 5. Calculate: B ≈ 34.99°

What we did and why: - We used tan because we had the opposite and adjacent sides. - Used tan⁻¹ (inverse tangent) to find the angle.


Example 3 – Exam Style (Word Problem)

Problem: A ladder leans against a wall at a 60° angle. If the base of the ladder is 4 m from the wall, how high up the wall does the ladder reach?

Solution: 1. Draw the triangle:
- Wall = Opposite (O)
- Ground = Adjacent (A) = 4 m
- Ladder = Hypotenuse (H)
- Angle = 60° 2. Choose ratio: We have A and need O → Use TANGENT (tan). 3. Write equation: tan(60°) = O / 4 4. Solve for O: O = 4 × tan(60°) 5. Calculate: O = 4 × 1.732 ≈ 6.93 m

What we did and why: - We used tan because we had the adjacent side and needed the opposite. - Multiplied the adjacent side by tan(θ) to find the height.


Common Mistakes

Mistake Why It Happens Correct Approach
Using the wrong ratio Confusing opposite/adjacent/hypotenuse Label the triangle first, then pick SOH-CAH-TOA.
Forgetting calculator mode Using radians instead of degrees Always check: DEG mode for angles in degrees.
Mixing up sides Calling the hypotenuse the adjacent side Hypotenuse is always opposite the 90° angle.
Incorrectly rearranging equations Forgetting to multiply/divide both sides Write the equation first, then solve step-by-step.
Rounding too early Rounding sin/cos/tan values before final answer Keep full decimals until the last step.

Exam Traps

Trap How to Spot It How to Avoid It
Non-right-angled triangles Question doesn’t mention a 90° angle Only use SOH-CAH-TOA for right-angled triangles.
Missing units Answer requires cm/m but isn’t specified Always include units in your final answer.
Disguised questions Word problems that don’t mention "triangle" Draw a diagram first to visualise the right angle.

1-Minute Recap

"Alright, let’s lock this in—tonight, before your exam, here’s what you need to remember:

  1. Label your triangle: Opposite, adjacent, hypotenuse—always relative to the angle you’re using.
  2. Pick the right ratio: SOH-CAH-TOA. If you have two sides, use the one that matches.
  3. Write the equation: Plug in the numbers, then solve.
  4. Check your calculator: DEGREE MODE! No radians.
  5. Double-check: Does the answer make sense? Hypotenuse is always the longest side.

You’ve got this. One question at a time, stay calm, and trust the steps. Good luck!




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