By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
"Ever wondered why a straw looks bent in water? That’s refraction—and mastering it unlocks 5-10 marks on your physics exam, from lens problems to fiber optics!
θ₂ = Angle of refraction (from the normal).
Speed of Light in a Medium (Given on exam sheet, but know how to use it) [ v = \frac{c}{n} ]
n = Index of refraction of the medium.
Critical Angle Formula (MEMORISE THIS) [ \sin \theta_c = \frac{n_2}{n_1} \quad \text{(where } n_1 > n_2\text{)} ]
Follow these steps for every refraction problem:
Label the incoming ray, angle of incidence (θ₁), and refracted ray.
Identify Given Values
If n isn’t given, check your formula sheet (e.g., n for water = 1.33).
Choose the Right Formula
Use critical angle formula if the question mentions total internal reflection.
Plug in the Numbers
If solving for an angle, use sin⁻¹ (inverse sine) on your calculator.
Check Units & Reasonableness
If n₁ < n₂, light bends toward the normal (e.g., air → water).
Write the Final Answer with Units
Problem: A light ray travels from air (n = 1.00) into glass (n = 1.52) at an angle of incidence of 30°. What is the angle of refraction?
Solution: 1. Draw a Diagram - Air (top) → Glass (bottom). - Normal line drawn at 90° to the surface. - Incoming ray at 30° to the normal.
θ₂ = ? (what we’re solving for)
Use Snell’s Law: n₁ sin θ₁ = n₂ sin θ₂
Plug in the Numbers [ 1.00 \times \sin 30° = 1.52 \times \sin \theta_2 ] [ 0.5 = 1.52 \times \sin \theta_2 ] [ \sin \theta_2 = \frac{0.5}{1.52} = 0.3289 ] [ \theta_2 = \sin^{-1}(0.3289) = 19.2° ]
Check Reasonableness
Since n₂ > n₁, light bends toward the normal → angle should be smaller than 30° (19.2° makes sense).
Final Answer [ \theta_2 = 19.2° ]
Problem: Light passes from water (n = 1.33) into air (n = 1.00) at an angle of 25°. What is the angle of refraction?
Solution: 1. Diagram: Water → Air, normal line, 25° incidence. 2. Given: n₁ = 1.33, n₂ = 1.00, θ₁ = 25°. 3. Formula: Snell’s Law. 4. Calculation: [ 1.33 \sin 25° = 1.00 \sin \theta_2 ] [ 1.33 \times 0.4226 = \sin \theta_2 ] [ \sin \theta_2 = 0.5621 ] [ \theta_2 = \sin^{-1}(0.5621) = 34.2° ] 5. Check: n₂ < n₁ → light bends away from normal → angle increases (34.2° > 25° ✔). 6. Answer: 34.2°
What we did and why: We used Snell’s Law to find the refracted angle when light moves from a slower medium (water) to a faster one (air). The angle increased because light speeds up.
Problem: A light ray enters an unknown liquid at 40° and refracts at 28°. If the first medium is air (n = 1.00), what is the index of refraction of the liquid?
Solution: 1. Diagram: Air → Liquid, normal line, 40° incidence, 28° refraction. 2. Given: n₁ = 1.00, θ₁ = 40°, θ₂ = 28°, n₂ = ? 3. Formula: Snell’s Law. 4. Calculation: [ 1.00 \sin 40° = n_2 \sin 28° ] [ 0.6428 = n_2 \times 0.4695 ] [ n_2 = \frac{0.6428}{0.4695} = 1.37 ] 5. Check: n₂ > n₁ → light bends toward normal → angle decreases (28° < 40° ✔). 6. Answer: 1.37
What we did and why: We rearranged Snell’s Law to solve for n₂ (the unknown liquid’s index). The angle decreased, confirming the liquid slows light more than air.
Problem: A fiber optic cable has a core with n = 1.48 and a cladding with n = 1.46. What is the critical angle for light traveling from the core to the cladding?
Solution: 1. Diagram: Core → Cladding, normal line, critical angle (θ_c). 2. Given: n₁ = 1.48 (core), n₂ = 1.46 (cladding). 3. Formula: Critical angle formula. 4. Calculation: [ \sin \theta_c = \frac{n_2}{n_1} = \frac{1.46}{1.48} = 0.9865 ] [ \theta_c = \sin^{-1}(0.9865) = 80.6° ] 5. Check: n₁ > n₂ → total internal reflection possible → critical angle exists (80.6° is reasonable). 6. Answer: 80.6°
What we did and why: We used the critical angle formula because the question asked for the angle where light stops refracting and reflects instead. This is key for fiber optics!
"Alright, let’s lock this in for your exam. Refraction is just light bending when it changes speed. Remember Snell’s Law: n₁ sin θ₁ = n₂ sin θ₂—that’s your golden ticket. Draw the normal, label your angles, and plug in the numbers. If n increases, light bends toward the normal; if n decreases, it bends away. For critical angles, use sin θ_c = n₂/n₁ when light goes from slow to fast. Watch out for examiners hiding the normal or swapping n₁ and n₂. Double-check your calculator is in degrees, not radians! You’ve got this—go ace that question!
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