By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
"If you can find the domain and range of any function, you’ll unlock 5–10 marks on your exam—and avoid losing points on word problems about real-world limits, like how high a drone can fly or how much profit a business can make!
For polynomials (linear, quadratic, cubic, etc.): - Domain is all real numbers (-∞ < x < ∞).
For rational functions (fractions): 1. Set the denominator ≠ 0. 2. Solve for x. 3. Exclude those x-values from the domain.
For square roots: 1. Set the inside ≥ 0. 2. Solve for x. 3. Domain is all x that satisfy the inequality.
For logarithms: 1. Set the inside > 0. 2. Solve for x. 3. Domain is all x that satisfy the inequality.
For piecewise functions: - Find the domain for each piece, then combine them.
Method 1: Use the Graph 1. Sketch or visualise the graph. 2. Look for the lowest and highest y-values. 3. Check for asymptotes (horizontal or vertical).
Method 2: Algebraic Approach - For quadratics (f(x) = ax² + bx + c): - If a > 0, range is [vertex y-value, ∞). - If a < 0, range is (-∞, vertex y-value]. - For linear functions (f(x) = mx + b): - Range is all real numbers (-∞ < y < ∞). - For rational functions: - Find horizontal asymptotes (if any) to determine limits. - For square roots: - Range starts at 0 and goes up (y ≥ 0).
Problem: Find the domain and range of f(x) = x² - 4x + 3.
Step 1: Identify the function type → Quadratic polynomial. Step 2: Domain → All real numbers (-∞ < x < ∞). Step 3: Range → Since a = 1 > 0, parabola opens upward. - Find vertex: x = -b/(2a) = 4/2 = 2. - f(2) = (2)² - 4(2) + 3 = 4 - 8 + 3 = -1. - Range: y ≥ -1 → (-1, ∞). Step 4: Write in interval notation. - Domain: (-∞, ∞) - Range: (-1, ∞)
What we did and why: - Polynomials always have a domain of all real numbers. - For quadratics, the range depends on the vertex and whether the parabola opens up or down.
Problem: Find the domain and range of f(x) = (x + 1)/(x - 3).
Step 1: Identify the function type → Rational function. Step 2: Domain → Denominator ≠ 0 → x - 3 ≠ 0 → x ≠ 3. - Domain: (-∞, 3) ∪ (3, ∞). Step 3: Range → Find horizontal asymptote. - Degree of numerator = degree of denominator → y = 1 (leading coefficients). - Check if y = 1 is ever reached: 1 = (x + 1)/(x - 3) → x - 3 = x + 1 → -3 = 1 (no solution). - Range: y ≠ 1 → (-∞, 1) ∪ (1, ∞). Step 4: Write in interval notation. - Domain: (-∞, 3) ∪ (3, ∞) - Range: (-∞, 1) ∪ (1, ∞)
What we did and why: - Rational functions are undefined where the denominator is zero. - Horizontal asymptotes help find the range, but we must check if the function ever equals the asymptote.
Problem: A drone is launched from the ground (y = 0). Its height in meters after t seconds is given by: - h(t) = -5t² + 20t for 0 ≤ t ≤ 4 - h(t) = 0 for t > 4
Find the domain and range of h(t).
Step 1: Identify the function type → Piecewise function. Step 2: Domain → Given by the problem: - 0 ≤ t ≤ 4 (drone is in the air) and t > 4 (drone has landed). - Domain: [0, ∞). Step 3: Range → Find max height of the quadratic part. - h(t) = -5t² + 20t (opens downward). - Vertex at t = -b/(2a) = -20/(2-5) = 2. - h(2) = -5(2)² + 20(2) = -20 + 40 = 20. - Range: 0 ≤ y ≤ 20 (since drone starts and ends at y = 0). Step 4: Write in interval notation. - Domain: [0, ∞) - Range: [0, 20]
What we did and why: - Piecewise functions require checking each part separately. - Word problems add restrictions (e.g., time can’t be negative, height can’t be negative).
"Alright, let’s lock this in for your exam. Domain is all the x-values your function can take. Range is all the y-values it can spit out. Here’s how to crush it:
Piecewise? Check each piece.
For range:
Word problems? Adjust for real-world limits.
Write it right:
You’ve got this. Now go practice 3 problems tonight, and you’ll own domain and range on exam day!
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