By Fatskills Exam Guides Team — the exam nerds behind 28,500+ quizzes and 2.1M practice questions across 500+ global exams.
(For Students Who Want to Ace Their Exam & Teachers Who Need a Ready-to-Record Script)
"If you can find an exterior angle in 10 seconds, you’ll save minutes on your exam—and minutes mean marks. Let’s make sure you never lose a point on this again."
Before tackling exterior angles, you must already understand: 1. Angles in a triangle – The sum of interior angles in any triangle is 180°. 2. Linear pairs – Two angles on a straight line add up to 180°. 3. Polygon basics – A polygon is a closed shape with straight sides (e.g., triangle, quadrilateral, pentagon).
If any of these are shaky, pause and review them first.
Formula: Exterior Angle = Sum of the Two Remote Interior Angles
Variables: - Let the exterior angle be at vertex A. - The two remote interior angles are at vertices B and C.
Example: If ∠B = 50° and ∠C = 70°, then the exterior angle at A = 50° + 70° = 120°.
MEMORISE THIS – This is not usually given on exam sheets.
Formula: Sum of Exterior Angles = 360° (for any polygon, no matter how many sides)
Variables: - Works for triangles, quadrilaterals, pentagons, etc.
Example: A hexagon has 6 exterior angles. Their sum is 360°.
GIVEN ON EXAM SHEET (but memorise it anyway—it saves time).
Formula: Each Exterior Angle = 360° ÷ Number of Sides
Variables: - Number of Sides = How many sides the polygon has (e.g., 5 for a pentagon).
Example: A regular octagon (8 sides) has exterior angles of 360° ÷ 8 = 45° each.
MEMORISE THIS – Examiners love testing this.
When to use: Given two interior angles, or one interior angle and the exterior angle.
Steps: 1. Identify the exterior angle – It’s the angle outside the triangle, formed by extending one side. 2. Find the two remote interior angles – These are the two angles not next to the exterior angle. 3. Add the two remote interior angles – Their sum equals the exterior angle. 4. Check with linear pair (optional) – The exterior angle + its adjacent interior angle = 180°.
Worked Example (Using Steps): Question: In triangle ABC, ∠A = 60° and ∠B = 50°. Find the exterior angle at C.
When to use: Any polygon (triangle, quadrilateral, etc.).
Steps: 1. Count the number of sides – e.g., pentagon = 5 sides. 2. Remember the rule – Sum of exterior angles = 360° (always). 3. Write the answer – No calculation needed!
Worked Example: Question: What is the sum of the exterior angles of a 12-sided polygon (dodecagon)? 1. Number of sides = 12. 2. Sum of exterior angles = 360° (always). 3. Answer: 360°.
When to use: Given a regular polygon (all sides and angles equal).
Steps: 1. Count the number of sides – e.g., hexagon = 6 sides. 2. Use the formula: Each exterior angle = 360° ÷ number of sides. 3. Calculate and simplify – Give the answer in degrees.
Worked Example: Question: Find the measure of one exterior angle of a regular decagon (10 sides). 1. Number of sides = 10. 2. Formula: 360° ÷ 10 = 36°. 3. Answer: 36°.
Question: In triangle PQR, ∠P = 40° and ∠Q = 60°. Find the exterior angle at R.
Solution: 1. Exterior angle at R is formed by extending QR. 2. Remote interior angles are ∠P (40°) and ∠Q (60°). 3. Add them: 40° + 60° = 100°. 4. Check: Exterior angle (100°) + interior angle at R (80°) = 180° ✔️
What we did and why: - We used the rule that an exterior angle equals the sum of the two remote interior angles. - This works because the three interior angles of a triangle add to 180°, and the exterior angle + its adjacent interior angle also add to 180°.
Question: A regular polygon has an exterior angle of 24°. How many sides does it have?
Solution: 1. Formula: Each exterior angle = 360° ÷ number of sides. 2. Rearrange: Number of sides = 360° ÷ exterior angle. 3. Plug in: 360° ÷ 24° = 15. 4. Answer: 15 sides.
What we did and why: - We used the formula for exterior angles in a regular polygon. - Since all exterior angles are equal, dividing 360° by one exterior angle gives the number of sides.
Question: In the figure below, AB is extended to D. If ∠CAB = 55° and ∠ABC = 45°, find ∠CBD.
(Note: ∠CBD is the exterior angle at B.)
Solution: 1. Identify the exterior angle – ∠CBD is outside the triangle, formed by extending AB. 2. Remote interior angles – ∠CAB (55°) and ∠ACB. 3. Find ∠ACB first – In triangle ABC, 55° + 45° + ∠ACB = 180° → ∠ACB = 80°. 4. Add remote angles: 55° + 80° = 135°. 5. Answer: ∠CBD = 135°.
What we did and why: - The question didn’t say "exterior angle," but we recognised ∠CBD as one. - We first found the missing interior angle (∠ACB) using the triangle angle sum. - Then we applied the exterior angle rule.
"Okay, let’s lock this in—30 seconds to master exterior angles, right before your exam.
Now go crush that exam. You’ve got this!
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